Can someone help me with these two questions?

(- 2, - 4 ) and (3, 10 )

Step-by-step explanation:

(2)

Given the 2 equations

4x - 7y = 20 → (1)

x - 3y = 10 → (2)

Rearrange (2) expressing x in terms of y, that is

x = 10 + 3y → (3)

Substitute x = 10 + 3y into (1)

4(10 + 3y) - 7y = 20 ← distribute and simplify left side

40 + 12y - 7y = 20

40 + 5y = 20 ( subtract 40 from both sides )

5y = - 20 ( divide both sides by 5 )

y = - 4

Substitute y = - 4 into (3) for corresponding value of x

x = 10 + 3(- 4) = 10 - 12 = - 2

Solution is (- 2, - 4 )

(3)

3x + y = 19 → (1)

4x - y = 2 → (2)

Adding the 2 equations term by term will eliminate the y- term

(4x + 3x) + (- y + y) = 19 + 2, that is

7x = 21 ( divide both sides by 7 )

x = 3

Substitute x = 3 into either of the 2 equations and solve for y

Substituting into (1)

3(3) + y = 19

9 + y = 19 ( subtract 9 from both sides )

y = 10

Solution is (3, 10 )