In isosceles △ABC, AB = BC and CH is an altitude. Find the perimeter of △ABC, if CH = 84 cm and m∠HBC = m∠BAC +m∠BCH

Approximately 360.3

Step-by-step explanation:

△ABC, AB = BC and CH is an altitude.

Note in isosceles triangle the two base angle are equal.

And two sides are equal.

CH = 84 cm and m∠HBC = m∠BAC +m∠BCH

So yhe base angle = 50°

The length of tthe hypotenuse , lets cal it x

Sin 50 = 84/x

X = 84/sin 50

109.65 = x

For the The base

109.65²-84²=b²/4

141 = b

Perimeter = 2*109.65 + 141

Perimeter = 360.3

Approximately 360

f

step-by-step explanation:

f

step-by-step explanation: