The center of a circle is at (-5 12) and it has a radius of 16. what is the equation of the circle?

(x+5)^2+(y-12)^2=256
(x+5)^2+(y-12)^2=4
(x-5)^2+(y+12)^2=256
(x-5)^2+(y+12)^2=4

(x+5)^2+(y-12)^2=256

Step-by-step explanation:

Comparing the given (x+5)^2+(y-12)^2=256

to                                   (x - h)^2 + (y - k)^2 = r^2,  

we see that h must be -5, k must be 12 and r must be 16.  This is the desired equation of the circle with center at (-5, 12) and radius 16.

(-1,-0.5)

step-by-step explanation:

hey seth! : )

i’m not 100% sure, but i think it’s b

hope this ya : p

miss u!

- nicole