Find the probability:
You roll a fair six-sided die twice. The first roll
shows a five and the second roll shows a six.

The probability is 1/36.

The outcome of the first roll does not affect the outcome of the second roll, and so the probability of rolling any number on a fair six-sided die remains 1/6 for both rolls. This means that the probability of rolling a 5 the first time and a 6 the second time are both 1/6, and to find the probability of 2 things happening we have to multiply, so we end up with 1/6 × 1/6 = 1/36

I hope this helps! Let me know if you have any questions :)

i dont get it. where are the "descriptions"?

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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