5) A bowl contains 6 tangerines and 4 apples. John randomly selects one piece of fruit, and then Pam randomly selects one of
the remaining pieces of fruit. What is the probability that John selects a tangerine and Pam selects an apple?

Pls help

5/18

Step-by-step explanation:

there are 9 pieces of fruit in the bowl,  tangerines and 5 clementines.

Assuming that they do not put the fruit back

P (tangerine) = number of tangerines/ total = 4/9

Then John keeps his and there are  8 pieces of fruit in the bowl,  

3 tangerines and 5 clementines.

P (Clementine) = number of clementines/ total = 5/8

P (tangerine, no replacement, Clementine) = P (tangerine) * P (Clementine)

                                                                       = 4/9 * 5/8 =5/18