4. Imagine that 41 randomly selected Miramar students are asked to measure the length of one
of their feet. Suppose that the sample mean foot length (x) turns out to be 23.4 centimeters and
that the sample standard deviation of the foot lengths turns out to be 5.1 centimeters.
a) Find a 95% confidence interval for ul, the mean foot length among all Miramar students.
(4 pts)
(2 pts each)
b) Would you expect about 95% of all Miramar students to have foot lengths within this
interval? Explain.
€

Which graph represents the following piecewise defined function?

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

Need this at the city museum, child admission is 6 and adult admission is 9.20. on tuesday, 132 tickets were sold for a total sales of 961.60. how many adult tickets were sold that day?