Consider the polynomial: StartFraction x Over 4 EndFraction – 2x5 + StartFraction x cubed Over 2 EndFraction + 1 Which polynomial represents the standard form of the original polynomial? StartFraction x cubed Over 2 EndFraction – 2x5 + StartFraction x Over 4 EndFraction + 1 –2x5 + StartFraction x cubed Over 2 EndFraction + StartFraction x Over 4 EndFraction + 1 –2x5 + StartFraction x Over 4 EndFraction + StartFraction x cubed Over 2 EndFraction + 1 1 – 2x5 + StartFraction x cubed Over 2 EndFraction + StartFraction x Over 4 EndFraction

(B)

–2x5 + StartFraction x cubed Over 2 EndFraction + StartFraction x Over 4 EndFraction + 1

Step-by-step explanation:

Given the polynomial:

We are required to pick an equivalent polynomial which is in standard form.

A polynomial is in standard form when it is written in descending powers of x.

Therefore, rearranging the polynomial above, we have:

The correct option is B.

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6