Una escalera está apoyada sobre la fachada de un edificio. Si la escalera mide 10 m de longitud y el pie de la escalera está a 5 m de la pared, ¿a qué altura de la pared llega la escalera? Expresa el resultado con radicales extrayendo todos los factores posibles.

8.66 meters

Step-by-step explanation:

Assuming that the building is completely straight, a right angle is formed and therefore a right triangle.

Thanks to this we can calculate the height at which the ladder reaches the wall using the Pythagorean theorem, this height being one of the legs.

We have to:

c ^ 2 = a ^ 2 + b ^ 2

c = 10

a = 5

replacing

b ^ 2 = 10 ^ 2 - 5 ^ 2

b ^ 2 = 75

b = 8.66

that is to say that the height at which the ladder reaches the wall is 8.66 meters

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>