(h,k) = (32,-4)
r = 32
Step-by-step explanation:
The general equation for a circle is given by:
(1)
where (h,k) is the center of the circle and r is the radius.
You have the following equation:
(2)
You first need to complete squares in order to obtain an equation of the form (1). Thus, you have that the second term must be in a perfect square trinomial:
2b = 64
b = 32
Then, you have to sum 32^2 and also subtract the same number in the expression (2):
![x^2-64x+(y+4)^2=0\\\\(x^2-64x+32^2)+(y+4)^2-32^2=0\\\\(x-32)^2+(y+4)^2=32^2](/tpl/images/0671/5742/91d9c.png)
you compare the last result with expression (1) and obtain that the raiuds of the circle is r = 32
Furthermore, the center of the circle is (h,k) = (32,-4)