Given: m∠ABC = 50°,
AC = 30
Find: OA

OA = 19.58

Step-by-step explanation:

If we draw the segments OA and OC, we will have an isosceles triangle OAC.

With the property of inscribed angles and central angles that are related to the same arc of the circunference, we have:

mAOC = 2 * mABC

mAOC = 2 * 50 = 100°

As the triangle OAC is isosceles, we have that mOAC = mACO.

Knowing that the sum of internal angles of a triangle is 180°, we have:

mACO + mOAC + 100 = 180

2 * mACO  = 80

mACO = 40°

Now, using the law of sines, we have:

OA / sin(ACO) = AC / sin(AOC)

OA / 0.6428 = 30 / 0.9848

OA = 30.463 * 0.6428 = 19.58

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

i dont know men

step-by-step explanation: