A spinner is divided into ten numbered sections, as shown.
(Assume the arrow never lands on a dividing line.)
With only one spin, what is the probability that the arrow
lands on an unshaded section or points to an even number?

The probability the spinner has to fall into an unshaded section or point to an even number is: 5/10 or 1/2

Step-by-step explanation:

To understand this answer we need to analyze the context. First of all, spinners usually are numbered from 1 to 10. Meaning that they have 5 even numbers and 5 odd numbers. Because 2,4,6,8,10 are even numbers and 1,3,5,7,9, are odd numbers considering even numbers can be cut in half to obtain complete numbers. Now, if there are 5 out of 10 we have a probability of getting 5/10 chances of an even number or unshaded section. Simplified to 1/2.

ab will be equal to