Suppose the length of an oarfish is normally distributed with a mean of 6.5 m and a standard deviation of 1.5 m. Which group describes 16% of the oarfish population? Select each correct answer. oarfish that are between 6.5 m and 9.5 m oarfish that are shorter than 5 m oarfish that are between 3.5 m and 9.5 m oarfish that are longer than 8 m

Step-by-step explanation:

Let x be the random variable representing the length of an oarfish. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

The given probability value is 16% = 0.16. From the normal distribution table, the z score corresponding to the probability value is - 0.99

This indicates that the sample mean is lower than the population mean

Therefore,

- 0.99 = (x - 6.5)/1.5

- 0.99 × 1.5 = x - 6.5

- 1.5 = x - 6.5

x = - 1.5 + 6.5

x = 5m

The correct answer is

oarfish that are shorter than 5 m

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

the answer is su.k.my? ? co.kc