Starting at time t = 0, the altitude of one helicopter is given by A1 = 600 + 150t, and the altitude of a second helicopter is given by A2 = 1250 + 50t. Which equation represents the difference of their altitudes A at time t?

The equation for difference in altitude of the two helicopters is A =  650 - 100t

Step-by-step explanation:

Given;

The altitude of one helicopter is, A1 = 600 + 150t

The altitude of a second helicopter is,  A2 = 1250 + 50t

Their difference in altitude, A at time t, is calculated as

A₂ - A₁  = A = (1250 + 50t) - (600 + 150t)

A₂ - A₁  = A =  1250 + 50t - 600 -150t

A₂ - A₁  = A = 1250 - 600 + 50t - 150t

A₂ - A₁  = A =  650 - 100t

Therefore, the equation for difference in altitude of the two helicopters is A =  650 - 100t

the radius is 2 times the diameter.

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.