Write your question here (Keep it simple and clear to get the best answer)A surveyor leaves her base camp and drives 42km on a bearing of 032degree, she then drives 28km on a bearing of 154degree

The surveyor is 36.1 km from the base camp and the base camp is a bearing of 253.4° away.

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Complete Question

A surveyor leaves her base camp and drives 42km on a bearing of 032°. She then drives 28km on a bearing of 154°. How far is she from her base camp and what is her bearing from it?

Solution

The diagram of the surveyor's movement is attached to this solution of the problem

From the attached image, the complete travel of the surveyor forms a triangle,

Naming the distance from her base camp y

Using Cosine rule

y² = 42² + 28² - (2×42×28×cos 58°)

y² = 2,548 - 1,246.37 = 1,301.63

y = √1,301.63 = 36.1 km

To obtain the surveyor's bearing from her base camp now, we use sine rule

[(Sin 58°)/y] = [(Sin a)/42]

Sin a = (42 × sin 58°)/36.1

a = sin⁻¹ (0.9866)

a = 80.6°

Bearing of the surveyor from the base camp = 270° - (80.6° - 64°) = 253.4°

Hope this Helps!!!

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