The dogs in an animal parade are grouped by size. There are 18 small dogs, 12 medium-sized dogs, and 10 large dogs. If one dog is randomly chosen to lead the parade, what is the probability that a medium-sized dog will be chosen

0.3

Step-by-step explanation:

Given:

Number of small dogs = 18

Number of medium-sized dogs = 12

Number of large dogs = 10

To find: probability that a medium-sized dog will be chosen

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Total number of dogs = 18 + 12 + 10 = 40

Number of medium-sized dogs = 12

So,

probability that a medium-sized dog will be chosen = Number of medium-sized dogs/Total number of dogs =

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/