Find the center and radius of the circle x2+(y+8)2=4

Center (0, -8) and Radius = 2

The standard equation of a circle is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

You can write the equation as (x-0)² + (y-( -8))² = 2². From this, you can conclude that the center is (0,-8) and the radius is 2.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

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step-by-step explanation: