You have $1000 to invest in an account and need to have $2000 in one year. What interest rate would you need to have in order to have this if the amount is compounded weekly? Round your answer to the nearest percent.

69.8%

Step-by-step explanation:

The weekly interest rate is computed using 52 weeks a year as per standard investment practice.

FV=PV*(1+r/52)^n*52

FV is the future value of $2000

PV is the present worth of $1,000

r is the unknown

n is the number of years which is 1

2000=1000*(1+r/52)^1*52

divide both sides by 1000

2000/1000=(1+r/52)^52

divide the index of the both sides by 52

(2000/1000)^(1/52)=1+r/52

1.013418991 =1+r/52

r/52=1.013418991 -1

r/52=0.013418991

r=0.013418991 *52=69.8%

1/4 and 8/3 because:

the reciprocal if 4 is 1/4 because 4 is used as 4/1 and the opposite of that is 1/4. the opposite of 3/8 is 8/3 so that is the answer.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752