Carla is going to draw a marble from the bag shown below, replace it, and then draw another marble. What is the probability that Carla will get a green or yellow marble on the first draw and a blue on the second draw? (3 green, 4 yellow, 5 blue, 8 pink)

7/80

Step-by-step explanation:

(3 green, 4 yellow, 5 blue, 8 pink) = 20 marbles

P ( green or yellow  ) = number of green or yellow / total

                = (3+4)/20  = 7/20

Replace  

so we have (3 green, 4 yellow, 5 blue, 8 pink) = 20 marbles

P (blue) = number of blue/ total

                = 5/20  = 1/4

P ( green or yellow, replace, blue) = 7/20 * 1/4 = 7/80          

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.