A) Find the difference between3y minutes and 25y second, giving your answer in second.
B) find the sum of 50(3z- 2) minutes and4(z+1) hour, giving your answer in second.
Pls tell answers of both question

155ysec ; 23400z+ 8400 secs

Step-by-step explanation:

3y mins = 3* 60=180y sec

3y mins - 25y sec= 180y sec - 25y= 155y sec

155ysec

From B

50(3z-2)min = 50 * 60 (3z-2) sec

= 3000(3z-2)=9000z-6000

4 (z + 1) hours =4*3600(z+1) =14400z + 14400z

Adding both expression we have;

9000z+14400z-6000+14400=23400z+ 8400 secs

23400z+ 8400 secs

27

step-by-step explanation:

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.