The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are 148, 102, 15zs2. What is the average of the extracted scores that are extreme values (outliers)

Solution:

The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

To find : average of the extracted scores that are the extreme values (outliers)

The average marks of candidates in an aptitude test was 128.5

=> Mean = 128.5

Standard Deviation = 8.2

outlier will be out sides   then range    Mean  ± 3* SD

128.5 ± 8.2 × 3

= 128.5 ± 24.6

Range is   ( 103.9  ,  153.1)

102 is outside this range

i would say the third one.

step-by-step explanation: liner would mean in a line and the only one that doesn't look like it's even thinking about forming a line would be the third one

the answer is (-4,-4)

hope this ! : d