The average mark of candidate in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are 148, 102,152. What is the average of the extracted scores t hat are extreme values (outliers)?

Step-by-step explanation:

Given that  : The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

The objective here is to determine the average of the extracted scores that are the extreme values (outliers)

NOW:

The average marks of candidates in an aptitude test was 128.5

i.e the Mean = 128.5

Standard Deviation = 8.2

outlier will be outsides;

then the range  will be    Mean  ± 3 × SD

= 128.5 ± 8.2 × 3

= 128.5 ± 24.6

Range is  ( 103.9  ,  153.1)

102 is outside this range

Hence, the average of the extracted scores that are extreme values (outliers) will be 102 only

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.