Ax^+bx+c=0 what is the root of this question

ax^² + bx + c =0

x(ax+b)+c=0

(ax+b)(x+c)=0

ax+b=0 or x+c=0

ax= -b or x= -c

x= -b/a. or x= -c

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step-by-step explanation:

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b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5