Find the Coordinates of a point A, where AB is diameter of a circle whose
centre is (2,-3) and B is (1,4)

(3, -10)

Step-by-step explanation:

let A(x,y) and B(x1,y1)=(1,4)

by midpoint formula i.e. (x+x1)/2 ; (y+y1)/2

as midpoint is centre so,

(2, -3) = (x+1)/2 ; (y+4)/2

2=(x+1)/2  and -3=(y+4)/2

4-1=x    and   -6-4=y

x=3       and    y=-10

therefore A(x,y)=A(3,-10)

we don't have enough info to solve this

the answer is 5636.7