Find the 96th term of the arithmetic sequence
-3, -14, -25, ...

The 96th term of the given AP is (-1048)

Step-by-step explanation:

We have, the given AP is :

-3, -14, -25....

First term is -3

Common difference is -14 - (-3)= -11

Let is the 96th term of the AP.

The nth term of the AP is given by :

Put all the values, such that,

So, the 96th term of the given AP is (-1048).

-8

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15