*WILL GIVE BRAINLIEST* the following function represents the production cost f(x), in dollars, for x number of units produced by company 1:

f(x)=0.05x^2-7x+300

The following table represents the production cost g(x), in dollars, for x number of units produced by company 2:

x g(x)
0.6 899.58
0.8 899.52
1 899.50
1.2 899.52
1.4 899.58

Based on the given information, determine which company has a lower minimum and find the minimum value.

a.) f(x) at (1, 899.50)
b.) g(x) at (70, 55)
c.) f(x) at (70, 55)
d.) g(x) at (1, 899.50)

C.

Step-by-step explanation:

By analyzing the functions f(x) and g(x), we can see that they are both quadratic relations.

To find the minimum value, we want to find the y-coordinate of the vertex.

In f(x), by using the formula (-b/2a), we get the x-coordinate of the vertex, 70. When we substitute 70 into the function, we get 55 as our minimum.

In h(x), we can see that the lowest y-coordinate in the given points is 899.52. So (1, 899.50) is our vertex.

This means that in f(x), the minimum production cost is $70. In contrast, in h(x), the minimum production cost is $899.50. Therefore f(x) has a lower minimum, with its minimum value at (70, 55), our vertex.

19.side- angle- side

20. angle- side- angle

step-by-step explanation:

part a

answer: a reasonable domain is where n is a real number. so n can be between 0 and 10. both endpoints are included.

work shown:

n is the number of days after the experiment starts. the smallest n can be is n = 0 which means that 0 days have gone by, and we're at the start. to find out how large n should be, then replace f(n) with 16.13 and solve for n. use logarithms to isolate the exponent.

f(n) = 12*(1.03)^n

16.13 = 12*(1.03)^n

16.13/12 = (1.03)^n

1.34416666666667 = (1.03)^n

(1.03)^n = 1.34416666666667

log[ (1.03)^n ] = log[ 1.34416666666667 ]

n*log[ 1.03 ] = log[ 1.34416666666667 ]

n = log[ 1.34416666666667 ]/log[ 1.03 ]

n = 10.0062999823929

this rounds to n = 10 which is fairly close but not 100% perfect. so this is the largest n can be.

note: if you plug n = 10 into f(n), you'll get roughly 16.127 which rounds to 16.13 (this comes up again in part c)

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part b

answer: the y intercept is 12. it represents the starting height of the plant in cm.

work shown:

plug n = 0 into the f(n) function. simplify

f(n) = 12*(1.03)^n

f(0) = 12*(1.03)^0

f(0) = 12*(1)

f(0) = 12

on day n = 0, aka the starting point, the height f(n) is 12 cm

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part c

answer: the average rate of change is approximately 0.43061036458991 (round however you need to). this represents the average growth rate from day n = 3 to day n = 10. so the plant grew roughly 0.43 cm per day during this timespan, assuming you round to 2 decimal places.

work shown:

compute f(3)

f(n) = 12*(1.03)^n

f(3) = 12*(1.03)^3

f(3) = 13.112724 < we'll use this later

compute f(10)

f(n) = 12*(1.03)^n

f(10) = 12*(1.03)^10

f(10) = 16.1269965521294 < we'll use this later

now use the formula below with a = 3 and b = 10

aroc = average rate of change

aroc = [ f(b) - f(a) ]/[ b - a ]

aroc = [ f(10) - f(3) ]/[ 10 - 3 ]

aroc = (16.1269965521294 - 13.112724)/(10 - 3)

aroc = 3.0142725521294/7

aroc = 0.43061036458991

round this however you need to

note: the plant grew approximately 3.01 cm over 7 days, so roughly 0.43 cm per day is the average growth rate (if you were to round to 2 decimal places).