![A+B=\theta\\B=\theta-A\\sin B=sin (\theta-A)\\sin A=\lambda[sin \theta cos A-cos \theta sin A]\\sin A[1+\lambda cos \theta]=cos A(\lambda sin \theta) \\\frac{sin A}{cosA} =\frac{\lambda sin \theta}{1+ \lambda cos \theta} \\](/tpl/images/0673/7462/9654b.png)
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