What is the equation of the parabola that has its vertex at (7,6) and contains the point (6,8)?

is the equation of parabola.

Step-by-step explanation:

Vertex form of a parabola is given as :

(h,k) is the co-ordinate of vertex of parabola.

(x,y) are the points on parabola.

We are given that vertex is at (7,6) and a point on parabola is (6,8).

h = 7

k = 6

x = 6 and

y =8

Putting all the values in equation (1):

Putting values of (h,k) and a in equation (1) to obtain the equation of parabola:

is the equation of parabola with vertex at (7,6) and contains the point (6,8).

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this