Mathematics, 03.06.2020 12:57 saabrrinnaaa
Parallelogram ABCD has vertices at A(0, 0) , B(3, 6) , C(5, 5) , and D(2,−1) . Which conclusion can be made? AC=BD; therefore, ABCD is a rhombus. AC¯¯¯¯¯⊥BD¯¯¯¯¯; therefore, ABCD is a rhombus. AC=BD; therefore, ABCD is a rectangle. AC¯¯¯¯¯⊥BD¯¯¯¯¯; therefore, ABCD is a rectangle.
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