List the intergers that satisfy both these inequalities 2x+9<0 and x>-12

-11, -10, -9, -8, -7, -6, -5, -4, -3, -2, -1

(would really, reallly appreciate the brainliest)

Step-by-step explanation:

2x+9 < 9

can be rewritten as

2x < 0

and therefore

x < 0

the other inequality states that x hat to be bigger then -12

so all integers that satisfy -12 < x < 0 are in the set we search, but be aware that -12 and 0 don't fall into this set, bc -12 for example isn't bigger than -12

The integers that satisfy both inequalities are -5, -6, -7, -8, -9, -10 and -11.

Step-by-step explanation:

Firstly, you have to solve the inequality :

Next, given that x is greater than -12 but smaller than -4.5 so the inequality for x is :

Integer is a positive or a negative number but 'cannot be written in the form of decimal'. So the integers that satisfy both inequalities are :

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

lol

step-by-step explanation: