The following is the distribution of a random variable X. X=0, 1, 2, 3
P(X)=0.1, 0.3, 0.4, 0.2
Find E(X)

And adding the values we got:

So then the expected value for this random variable would be

Step-by-step explanation:

For this case we have the following probability distribution given:

X       0     1      2     3

P(X)  0.1  0.3  0.4  0.2

And for this case the expected value with the following formula:

And replacing we have:

And adding the values we got:

So then the expected value for this random variable would be

the car was traveling 40 mph before it started skidding. ( 2 points ) 17. was the driver were her brakes working at 75% efficiency or better? ( 2 points ) yes 29.

step-by-step explanation:

5

step-by-step explanation: