Aloysius and Benjamin have $150 altogether. Aloysius' mother gives him another $40 and Benjamin spends $ 10 on a book. Benjamin then has $10 more than Aloysius . How much money does each of them have at first?

Aloy has $55 initially

Benjamin has $95 initially

Step-by-step explanation:

In this question, given the order in which the money flowed in the question, we want to know how much each of the two had initially.

let what Aloys have be x and what Benjamin has be y.

Together, they had 150

x + y = 150 ••••••••(i)

Aloys mother gave him 40, new money is x + 40, Benjamin spent 10, new money is y-10

the new difference is 10

Thus;

(x + 40)-(y-10) = 10

x + 40 -y + 10 = 10

x+ 40 = y

substitute this into the first equation

x + 40 + x = 150

2x + 40 = 150

2x = 150-40

2x = 110

x = 110/2

x = $55

y = x + 40 = 55 + 40 = $95

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answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column