A box in the shape of a rectangular prism, with dimensions 12 inches by 18 inches by 12 inches, can hold exactly 12 cubes measuring 6 inches on each side.
If the length and width of the base are doubled, how many cubes could the new box hold?
18
OOO
24
48
96

48 cubes

Step-by-step explanation:

Hi, to answer this question, first we have to calculate the dimensions of the box:

Length = 12 in x 2 (doubled) = 24in

Width= 18 in x 2 (doubled) = 36in

Height = 12

Now, we have to calculate the volume of the box:

Volume of a rectangular prism = length x width x height = 24x36x12 = 10,368in3

Volume of the cubes= side length ^3 =6 ^3 = 216 in3

Finally we have to divide the volume of the box by the volume of each cube:

10,368 / 216 =48 cubes

Feel free to ask for more if needed or if you did not understand something.  

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: