Please help! Correct answer only! I've been on this question for more than an hour...

You pick a card at random. Without putting the first card back, you pick a second card at random.

What is the probability of picking a 3 and then picking a 3?

Simplify your answer and write it as a fraction or whole number.

You have three card : 3, 4, 5 and 6.

You first pick one card randomly, the probability of picking a 3 is:

P = 1/4

You then pick a second card without putting the first card back, the probability of picking a 3 is:

P = 1/3

=> The probability of picking a 3 and then picking a 3:

P = (1/4) x (1/3) = 1/12

Hope this helps!

:)

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

6 and 24

step-by-step explanation:

6 x 4 = 24