I will ark the brinlest to the first person who answers. A student submitted a drawing of their playroom with a scale of 2 inches = 5 feet. On the drawing, the playroom was 6.5 inches wide and 9.25 inches long. What is the ACTUAL AREA of the playroom? (round to the nearest tenth; show your work in numbers)

area = 375.8 ft^2

Step-by-step explanation:

The scale is 2 inches = 5 feet.

The room is 6.5 inches wide in the drawing. We need the real width, x.

2 in./5 ft = 6.5 in./x

2x = 5 * 6.5

2x = 32.5

x = 16.25

The real width is 16.25 ft.

The room is 9.25 inches wide in the drawing. We need the real length, y.

2 in./5 ft = 9.25 in./y

2y = 5 * 9.25

2x = 46.25

x = 23.125

The real length is 23.125 ft.

Area of rectangle = length * width

area = 23.125 ft * 16.25 ft

area = 375.78125 ft^2

area = 375.8 ft^2

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

it is only things thain can be deafeated

step-by-step explanation: