B) David and Andrew are traveling to a Mathematics conference. David travels 110 miles in the same time that Andrew travels 140 miles. Andrew travels 15 miles per hour faster than David. Find the average rate of each person.

David's average speed is 55 mph and Andrew's average speed is 70 mph

Step-by-step explanation:

Let David's speed be s.

Average speed is given as:

speed = distance / time

They both spent the same time, t.

David's speed is:

s = 110 / t

=> t = 110 / s

Andrew travels 15 mph faster than David.

Andrew's speed is:

(15 + s) = 140 / t

=> t = 140 / (15 + s)

Therefore, since they spent the same time:

110 / s = 140 / (15 + s)

Cross multiply:

110(15 + s) = 140s

1650 + 110s = 140s

1650 = 140s - 110s

30s = 1650

s = 1650 / 30

s = 55 mph

Andrew's speed is:

15 + 55 = 70 mph

Therefore, David's average speed is 55 mph and Andrew's average speed is 70 mph.

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hope it's you

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116