Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ. n = 2136, p = 3/7

Answers:

1. Minimum: 843.1; maximum: 987.75

2. Minimum: 961.17; maximum: 869.69

3. Minimum: 892.56; maximum: 938.3

4. Minimum: 869.69; maximum: 961.17

And the best option would be:

4. Minimum: 869.69; maximum: 961.17

Step-by-step explanation:

We can assume that the variable of interst X is distributed with a binomial distribution and we can use the normal approximation.

For this case the mean would be given by:

And the standard deviation would be:

And if we find the limits we got:

And the best option would be:

4. Minimum: 869.69; maximum: 961.17

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step-by-step explanation:

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step-by-step explanation: