Integral cos(3x)^3sen(3x)^7dx

One way to do this is to exploit the Pythagorean identity,

to rewrite

so that

Then substitute and to get the integral

which is one correct form of the antiderivative. There's no reason we can't use the identity from before to express the integrand in terms of powers of cos(3x) instead.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation: