A number is selected from the set {1, 2, 3, 5, 15, 21, 29, 38, 500}. If equal elemental probabilities are assigned, what is the probability that the number chosen is either less than 29 or odd? 6/9 7/9 8/9

The required probability is .

Step-by-step explanation:

Set given is:

S = {1, 2, 3, 5, 15, 21, 29, 38, 500}

Total number of elements in set, = 9

Let A be the event that the number is less than 29 ({1, 2, 3, 5, 15, 21}).

Number of items in the event A, = 6

Probability of event A,

Formula for probability of any event E:

Let B be the event that the number is odd (either of {1,3,5,15,21,29}).

Number of items in the event B, = 6

Probability of event B,

The event A and B have a few elements in common, i.e. numbers less than 29 which are odd as well.

The common elements are represented as:

To find probability of selecting a number which is either less than 29 (event A) or odd (event B),

We have to find which is represented as and the formula is:

The required probability is .

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0

answer: graph 2

step-by-step explanation: