subject
Mathematics, 05.06.2020 08:59 tttyson

An investment of $75000 can be modeled by the equation V(t)= 75000(1.125)^t, where V(t) is the value of an investment and t is time in years after the year 2015. a. What is the rate of increase of the investment after the year 2015?

b. How much was invested in the year 2015?

c. What will the investment be in 2020?

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 20:30
If g^-1(x) is the inverse of g (x) which statement must be true
Answers: 3
question
Mathematics, 21.06.2019 23:10
Frank is lending $1,000 to sarah for two years. frank and sarah agree that frank should earn a real return of 4 percent per year. instructions: a. the cpi (times 100) is 100 at the time that frank makes the loan. it is expected to be 113 in one year and 127.7 in two years. what nominal rate of interest should frank charge sarah?
Answers: 3
question
Mathematics, 22.06.2019 00:00
Fill in the blank 1. a rhombus is a rectangle a) always b) sometimes c) never 2. a square is a quadrilateral a) always b) sometimes c) never 3. a trapezoid is a kite a) always b) sometimes c) never 4. a quadrilateral is a kite a) always b) sometimes c) never 5. a square is a rhombus a) always b) sometimes c) never 6. a parallelogram is a rectangle a) always b) sometimes c) never
Answers: 1
question
Mathematics, 22.06.2019 04:10
Amy is plan her school's new basketball court. the west edge of the basketball court is located on the line y = 5x + 2. the east edge cannot intersect with the west edge. on which line could the east edge be located? −y − 5x = 100 y + 5x = 100 −5x − y = 50 5x − y = 50
Answers: 2
You know the right answer?
An investment of $75000 can be modeled by the equation V(t)= 75000(1.125)^t, where V(t) is the value...
Questions
question
Mathematics, 20.02.2020 02:56
question
Mathematics, 20.02.2020 02:56
Questions on the website: 13722359