Teo has a combination of quarters, loonies, and toonies in his pocket. He knows he has 9 coins in total and that he has at least one of each
type of coin.
a) What is the probability that Teo has more than $8?

b) How many different combinations of coins could Teo use to pay for an item
that costs between $10 and $12, if he uses fewer toonies than loonies?

ooga booga ooga booga ooga booga ooga booga

Step-by-step explanation:

343

Step-by-step explanation:

There are quarters(25¢), loonies ($1), and toonies ($2)

And total number of coins is 9

If loonies ($1), and toonies ($2) are one, then quarters(25¢) is 7

If quarters(25¢), and toonies ($2) are one, then loonies ($1)is 7

If loonies ($1), and quarters(25¢) are one, then toonies ($2) is 7

So possible number number of combination for an item that cost between $10 and $12 is

= 1^3 * 1^3 * 7^3

= 343

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

if the probability is 1/12, 75 people will receive a $25 gift card

step-by-step explanation: