What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x= -b IVb2 - 400
20
x = 5110/5
N
x= -5110,5
N
0 x = -52/5
o x=575

   x  =  

Step-by-step explanation:

Given equation f(x) = x² + 5 x +5

The roots of the Quadratic equation   ax²+bx+c =0 are

Given equation f(x) = x² + 5 x +5

comparing           ax²+bx+c =0 is

                a = 1 , b = 5 and c = 5

            x  =  

             x  = -7.76 ,  x = -2.76 ,

1/800 is the right answer

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363