Determine the discriminant for the quadratic equation 0=-2x2+3. Based on the discriminant value, how many real number solutions does the equation have? Discriminant = b2-4ac

0

1

2

24

Option D.

The discriminat is equal to 24 which

Step-by-step explanation:

The quadratic equation is

-2x² + 3 = 0

Discriminat in quadratic equation tells us the number of solution a quadratic equation has.

For example, the quadratic equation

Ax² + bx + c = 0 will have a discriminat of b² - 4ac.

b² - 4ac is equal to the value of the discriminat and equal to the number of solutions the quadratic equation has.

In our question, we have -2x² + 3 = 0

A = -2

B = 0

C = 3

b² - 4ac = 0

Substitute the values into the above equation.

0² - 4(-2 ×3) = 0

0 + -4 × -6 = 0

24 = 0

The discriminat of the equation is 24

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!