There are 24 students in the class. If 12 of them enrolled to the French courses, 13 of them to the Spanish and 7 of them take neither, what is the probability that a randomly-chosen student from this group is taking only the French class?

1/6 = 0.1667 = 16.67%

Step-by-step explanation:

If there are 24 students in the class and 7 of them take neither courses, we have 17 students that take one or both courses.

To find the students that took both courses, we can use the formula:

N(Spanish or French) = N(Spanish) + N(French) - N(Spanish and French)

17 = 13 + 12 - N(Spanish and French)

N(Spanish and French) = 8

Then, the number of students that are taking only French is:

N(only French) = N(French) - N(Spanish and French)

N(only French) = 12 - 8 = 4

So the probability of chosing a student that took only French is:

P(only French) = N(only French) / N(total)

P(only French) = 4 / 24 = 1/6

answer: $201

step-by-step explanation: to get the answer, you first get 3 nieces that he sold and multiply it by 67 and get $201, so he earned $201 selling his nieces.