A fair coin is tossed, and a marble is chosen from the bag whose contents are shown below. 3 red marbles, 3 blue marbles, and 4 green marbles. What is the probability of the coin landing heads up and a blue (B) marble being randomly selected?

3/20

Step-by-step explanation:

Red = 3

Blue = 3

Green = 4

Total = 3+3+4 = 10

Pr (red) = 3/10

Pr blue) = 3/10

Pr (green) = 4/10

Where Pr = probability

You either have a head or a tail when tossing a coin

Probability of having head = 1/2

Probability of having tail = 1/2

The probability of the coin landing heads up and blue marble = Probability of head ×Pr (blue)

= 1/2 × 3/10

the probability of the coin landing heads up and blue marble = 3/20

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right