What is the measure of arc BC

Option B

Step-by-step explanation:

As property of angle inside circle, arc BC = 2 x angle BDC.

Let's consider triangle ABD.

BAD = 98 deg  

ABD = (1/2) x arc AD = (1/2) x 80 = 40 deg

As the property of sum of 3 angles in a triangle,

=> ADB + ABD + BAD = 180

=> ADB = 180 - ABD - BAD = 180 - 40 - 98 = 42 deg

=> BDC = 70 - 42 = 28

=> arc BC = 2 x 28 = 56 deg

=> Option B is correct

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.