Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of three students are possible? 7 C 3 = StartFraction 7 factorial Over (7 minus 3) factorial 3 factorial 7 35 70 210

The number of different combinations of three students that are possible is 35.

Step-by-step explanation:

Given that three out of seven students in the cafeteria line are chosen to answer a survey question.

The number of different combinations of three students that are possible is given as:

7C3 (read as 7 Combination 3)

xCy (x Combination y) is defines as

x!/(x-y)!y!

Where x! is read as x - factorial or factorial-x, and is defined as

x(x-1)(x-2)(x-3)...2×1.

Now,

7C3 = 7!/(7 - 3)!3!

= 7!/4!3!

= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)

= (7×6×5)/(3×2×1)

= 7×5

= 35

Therefore, the number of different combinations of three students that are possible is 35.

35

Step-by-step explanation:

i took the quiz on edg

if im undersanding the question correctly, its organized from 10

step-by-step explanation: