Use technology to solve the following problem: The mean annual income for people in a certain city (in thousands of dollars) is 44, with a standard deviation of 35. A pollster draws a sample of 59 people to interview. What is the probability that the sample mean income is between 42 and 48 (thousands of dollars)?

And we can use the z score formula given by:

And if we find the z scores for the limits of the interval we got:

And we want to find this probability:

And we can use the foolowing excel command and we got:

=NORM.DIST(0.878;0;1;TRUE)-NORM.DIST(-0.4;0;1;TRUE)

And we got:

Step-by-step explanation:

For this case we know the following parameters:

We select a sample size of n =59. So then the sample size is large enough to use the central limit theorem and the distribution for the sample mean is given by:

We want to find the following probability:

And we can use the z score formula given by:

And if we find the z scores for the limits of the interval we got:

And we want to find this probability:

And we can use the foolowing excel command and we got:

=NORM.DIST(0.878;0;1;TRUE)-NORM.DIST(-0.4;0;1;TRUE)

And we got:

3,750 deer

step-by-step explanation:

1,500 is 15 times larger than 100

lets make 250 15 times larger.

3750 deer

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116