The concession stand at the high school football stadium sells hot dogs and sodas. Jack bought 3 hotdogs and 2 sodas for a total of $12. Angie bought 1 hotdog and 4 sodas for $9. Solve a system of equations to determine the cost of 1 hotdog and 1 soda.

each soda costs $1.5 and each hotdog costs $3.

Step-by-step explanation:

If H is the price for one hotdog and S is the price for one soda, we have the equations:

for Jack.

3*H + 2*S = $12

For Angie.

1*H + 4*S = $9

Now we can isolate one of the variables in one of the equations and then replace it in the other equation, let's isolate H in the second equation:

H = $9 - 4*S

now we replace it in the first eq

3*H + 2*S = $12

3*($9 - 4*S) + 2*S = $12

$27 - 12*S + 2*S = $12

-10*S = $12 - $27 = -$15

S = $15/10 = $1.5

Now we can replace it in the equation for H and get:

H = $9 - 4*$1.5 = $3

So each soda costs $1.5 and each hotdog costs $3.

One hotdog cost $3 and One soda costs $1.5

Step-by-step explanation:

Let hotdogs be denoted by h

Let sodas be denoted as s

Jack bought 3 hotdogs and 2 sodas for a total of $12. This can be written as:

3h + 2s = 12

Angie bought 1 hotdog and 4 sodas for $9. This can be written as:

h + 4s = 9

3h + 2s = 12

h + 4s = 9

1 × (3h + 2s = 12)

3 × (h + 4s = 9)

3h + 2s = 12

3h + 12s = 27

Subtract the equation

-10s = -15

s = -15/-10

s = 1.5

One soda cost $1.5

Since h + 4s = 9

h + 4(1.5) = 9

h = 9 - 6

h = 3

One hotdog costs $3

you answer is a

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.