Four friends were born on consecutive years. the sum of their ages is 62. what is the age of the youngest friend?

Four friends were born on consecutive years.
The sum of their ages is 62. Let's find the age of the youngest friend:
Formula:
4x + 6 = 62
=> First is to Subtract 6 from both sides 4x = 56
Then next thing to do is to divide 4 from both sides:
=> x = 14 14 + 14 + 1 + 14 + 2 + 14 + 3 = 62
 62 = 62
 Thus the youngest age is 14

The answer should be c.