Terry bought some gum and some candy. The number of packs of chewing gum was one more than the number of mints. The number of mints was three times the number of chocolate bars. If gum cost 6 cents a pack, mints cost 3 cents each, and chocolate bars cost 10 cents each, how many of each confection did he get for 80 cents?

number of packs of chewing gum is 7

number of mints  is 6

number of chocolate bars is 2

Step-by-step explanation:

number of packs of chewing gum → x,  cost 6¢

number of mints → y = x-1 =3z,  cost  3¢

number of chocolate bars → z = y/3 = (x-1)/3, cost 10¢

put in equation 6x + 3y +10z = 80 plug in term of x

6x +3(x-1) +10((x-1)/3) =80 multiply each side by 3

18x +9(x-1) +10(x-1) =240 distribute

18x+9x-9+10x-10 =240 combine like terms

37x-19 = 240 add 19 in each side

37x =259

x = 7

plug into y = x-1 = 7-1 = 6 so y=6

and  z = y/3 =6/3 =2 so z = 2

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.

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step-by-step explanation: